C Program to Multiply Two 3 X 3 Matrices

Program : 

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#include<stdio.h>   int main() {    int a[10][10], b[10][10], c[10][10], i, j, k;    int sum = 0;      printf("\nEnter First Matrix : n");    for (i = 0; i < 3; i++) {       for (j = 0; j < 3; j++) {          scanf("%d", &a[i][j]);       }    }      printf("\nEnter Second Matrix:n");    for (i = 0; i < 3; i++) {       for (j = 0; j < 3; j++) {          scanf("%d", &b[i][j]);       }    }      printf("The First Matrix is: \n");    for (i = 0; i < 3; i++) {       for (j = 0; j < 3; j++) {          printf(" %d ", a[i][j]);       }       printf("\n");    }      printf("The Second Matrix is : \n");    for (i = 0; i < 3; i++) {       for (j = 0; j < 3; j++) {          printf(" %d ", b[i][j]);       }       printf("\n");    }      //Multiplication Logic    for (i = 0; i <= 2; i++) {       for (j = 0; j <= 2; j++) {          sum = 0;          for (k = 0; k <= 2; k++) {             sum = sum + a[i][k] * b[k][j];          }          c[i][j] = sum;       }    }      printf("\nMultiplication Of Two Matrices : \n");    for (i = 0; i < 3; i++) {       for (j = 0; j < 3; j++) {          printf(" %d ", c[i][j]);       }       printf("\n");    }      return (0); }

Steps :

1 2	Dimension of Matrix 1 : 1 X 3 Dimension of Matrix 2 : 3 X 2

Multiplication is Possible iff -

1	No. of Columns of Matrix 1 = No of Columns of Matrix 2

Resultant Matrix Will of Dimension-

1	c[No. of Rows of Mat1][No. of Columns of Mat2]

Steps 1 :

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Evaluate : 1 X 2  = 2 Evaluate : 4 X 5  = 20 Evaluate : 6 X 7  = 22 ------------------------- Add      :          64  ///c[0][0]

Step 2 :

1 2 3 4 5

Evaluate : 1 X 3  = 3 Evaluate : 4 X 8  = 40 Evaluate : 6 X 9  = 54 ------------------------- Add      :          89   ///c[0][1]

Programmable Implementation :

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//Multiplication Logic for (i = 0; i <= 2; i++) {   for (j = 0; j <= 2; j++) { sum = 0; for (k = 0; k <= 2; k++) { sum = sum + a[i][k] * b[k][j]; } c[i][j] = sum;   } }